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Example 5 (ii) - Chapter 9 Class 8 Algebraic Expressions and Identities
Last updated at March 22, 2023 by Teachoo
Examples
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Example 5 (i)
Example 5 (ii) Important You are here
Example 6 (i)
Example 6 (ii) Important
Example 7
Example 8 (i)
Example 8 (ii)
Example 9 (i)
Example 9 (ii) Important
Example 10
Example 11 (i)
Example 11 (ii) Important
Example 12 (i)
Example 12 (ii) Important
Example 13 (i)
Example 13 (iii)
Example 13 (ii) Important
Example 14 (i)
Example 14 (ii) Important
Transcript
Example 5 Simplify the expressions and evaluate them as directed: (ii) 3π¦(2π¦β7)β3(π¦β4)β63 for π¦=β2 3π¦(2π¦β7)β3(π¦β4)β63 =3π¦Γ2π¦β3π¦Γ7β3Γπ¦+3Γ4β63 =6π¦^2β21π¦β3π¦+12β63 =6π¦^2β24π¦β51 For y = βπ Putting π¦=β2 in expression 6π¦^2β24π¦β51 = 6(β2)^2β24(β2)β51 =6Γ4+24Γ2β51 = 24+48β51 = 72β51 = ππ
