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Example 8 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 2

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Example 8 Multiply (ii) (π‘₯ – 𝑦) and (3π‘₯ +5𝑦) (π‘₯βˆ’π‘¦)Γ—(3π‘₯+5𝑦) = π‘₯(3π‘₯+5𝑦)βˆ’π‘¦(3π‘₯+5𝑦) = (π‘₯Γ—3π‘₯)+(π‘₯Γ—5𝑦)βˆ’(𝑦×3π‘₯)βˆ’(𝑦×5𝑦) = 3π‘₯^2+5π‘₯π‘¦βˆ’3𝑦π‘₯βˆ’5𝑦^2 = 3π‘₯^2+5π‘₯π‘¦βˆ’3π‘₯π‘¦βˆ’5𝑦^2 = πŸ‘π’™^𝟐+πŸπ’™π’šβˆ’πŸ“π’š^𝟐

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.