Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
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Last updated at May 29, 2023 by Teachoo
Example 12 Using Identity (II), find (i) (4πβ3π)^2 (4πβ3π)^2 (πβπ)^2=π^2+π^2β2ππ Putting π = 4π & π = 3π = (4π)^2+(3π)^2β2(4π)(3π) = (4^2Γπ^2 )+(3^2Γπ^2 )β(2Γ4Γ3)Γ(πΓπ) = πππ^π+ππ^πβππππ