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Example 14 (ii) - Chapter 9 Class 8 Algebraic Expressions and Identities
Last updated at March 22, 2023 by Teachoo
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Transcript
Example 14 Use the Identity (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ to find the following: (ii) 95 Γ 103 95 Γ 103 = (100β5)Γ(100+3) = [100+(β5)]Γ[100+3] (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ Putting π₯ = 100 , π = β5 & π = 3 = (100)^2+(β5+2)(100)+(β5)(3) = 10000+(β2Γ100)+(β15) = 10000β200β15 = 1000β215 = ππππ
