![Example 14 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 3](https://d1avenlh0i1xmr.cloudfront.net/4009ef88-9778-4fa9-8afd-fb42fa542ddb/slide35.jpg)
Examples
Last updated at April 16, 2024 by Teachoo
Example 14 Use the Identity (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ to find the following: (ii) 95 Γ 103 95 Γ 103 = (100β5)Γ(100+3) = [100+(β5)]Γ[100+3] (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ Putting π₯ = 100 , π = β5 & π = 3 = (100)^2+(β5+2)(100)+(β5)(3) = 10000+(β2Γ100)+(β15) = 10000β200β15 = 1000β215 = ππππ