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Example 4 - Chapter 9 Class 8 Algebraic Expressions and Identities

Last updated at Dec. 24, 2018 by

Example 4 - Find the volume of each rectangular box with given length

Example 4 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 2
Example 4 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 3

Transcript

Example 4 (i) Find the volume of each rectangular box with given length, breadth and height. Length = 2ax, Breadth = 3by, Height = 5cz Volume = Length Γ— Breadth Γ— Height = 2aπ‘₯ Γ— 3by Γ— 5cz = 2 Γ— π‘Ž Γ— π‘₯ Γ— 3 Γ— b Γ— y Γ— 5 Γ— c Γ— z = (2 Γ— 3 Γ— 5) Γ— ( a Γ— b Γ— c Γ— π‘₯ Γ— y Γ— z) = 30abcxyz Example 4 (ii) Find the volume of each rectangular box with given length, breadth and height. Length = π’Ž^𝟐 𝒏, Breadth = 𝒏^𝟐 𝒑, Height = 𝒑^𝟐 π’Ž Volume = Length Γ— Breadth Γ— Height = π‘š^2 𝑛 Γ— 𝑛^2 𝑝 Γ— 𝑝^2 π‘š = π‘š^2x 𝑛 Γ— 𝑛^2 Γ— p Γ— 𝑝^2 Γ— π‘š = (π‘š^2 Γ— π‘š) Γ— (𝑛 Γ— 𝑛^2) Γ— (𝑝^2x 𝑝) = π‘š^3 Γ— 𝑛^3 Γ— 𝑝^3 = π’Ž^πŸ‘ 𝒏^πŸ‘ 𝒑^πŸ‘ Example 4 (iii) Find the volume of each rectangular box with given length, breadth and height. (iii) Length = πŸπ’’ , Breadth = γ€–πŸ’π’’γ€—^𝟐, Height = γ€–πŸ–π’’γ€—^πŸ‘ Volume = Length Γ— Breadth Γ— Height = 2π‘ž Γ— γ€–4π‘žγ€—^2 Γ— γ€–8π‘žγ€—^3 = 2 Γ— π‘ž Γ— 4 Γ— π‘ž^2 Γ— 8 Γ— π‘ž^3 = (2 Γ— 4 Γ— 8) Γ— (π‘ž Γ— π‘ž^2 Γ— π‘ž^3) = 64 Γ— π‘ž^6 = πŸ”πŸ’π’’^πŸ”

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.