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  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Serial order wise

Transcript

Example 4 (i) Find the volume of each rectangular box with given length, breadth and height. Length = 2ax, Breadth = 3by, Height = 5cz Volume = Length ร— Breadth ร— Height = 2a๐‘ฅ ร— 3by ร— 5cz = 2 ร— ๐‘Ž ร— ๐‘ฅ ร— 3 ร— b ร— y ร— 5 ร— c ร— z = (2 ร— 3 ร— 5) ร— ( a ร— b ร— c ร— ๐‘ฅ ร— y ร— z) = 30abcxyz Example 4 (ii) Find the volume of each rectangular box with given length, breadth and height. Length = ๐’Ž^๐Ÿ ๐’, Breadth = ๐’^๐Ÿ ๐’‘, Height = ๐’‘^๐Ÿ ๐’Ž Volume = Length ร— Breadth ร— Height = ๐‘š^2 ๐‘› ร— ๐‘›^2 ๐‘ ร— ๐‘^2 ๐‘š = ๐‘š^2x ๐‘› ร— ๐‘›^2 ร— p ร— ๐‘^2 ร— ๐‘š = (๐‘š^2 ร— ๐‘š) ร— (๐‘› ร— ๐‘›^2) ร— (๐‘^2x ๐‘) = ๐‘š^3 ร— ๐‘›^3 ร— ๐‘^3 = ๐’Ž^๐Ÿ‘ ๐’^๐Ÿ‘ ๐’‘^๐Ÿ‘ Example 4 (iii) Find the volume of each rectangular box with given length, breadth and height. (iii) Length = ๐Ÿ๐’’ , Breadth = ใ€–๐Ÿ’๐’’ใ€—^๐Ÿ, Height = ใ€–๐Ÿ–๐’’ใ€—^๐Ÿ‘ Volume = Length ร— Breadth ร— Height = 2๐‘ž ร— ใ€–4๐‘žใ€—^2 ร— ใ€–8๐‘žใ€—^3 = 2 ร— ๐‘ž ร— 4 ร— ๐‘ž^2 ร— 8 ร— ๐‘ž^3 = (2 ร— 4 ร— 8) ร— (๐‘ž ร— ๐‘ž^2 ร— ๐‘ž^3) = 64 ร— ๐‘ž^6 = ๐Ÿ”๐Ÿ’๐’’^๐Ÿ”

About the Author

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.