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Example 4 - Find the volume of each rectangular box with given length

Example 4 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 2
Example 4 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 3

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Example 4 (i) Find the volume of each rectangular box with given length, breadth and height. Length = 2ax, Breadth = 3by, Height = 5cz Volume = Length Γ— Breadth Γ— Height = 2aπ‘₯ Γ— 3by Γ— 5cz = 2 Γ— π‘Ž Γ— π‘₯ Γ— 3 Γ— b Γ— y Γ— 5 Γ— c Γ— z = (2 Γ— 3 Γ— 5) Γ— ( a Γ— b Γ— c Γ— π‘₯ Γ— y Γ— z) = 30abcxyz Example 4 (ii) Find the volume of each rectangular box with given length, breadth and height. Length = π’Ž^𝟐 𝒏, Breadth = 𝒏^𝟐 𝒑, Height = 𝒑^𝟐 π’Ž Volume = Length Γ— Breadth Γ— Height = π‘š^2 𝑛 Γ— 𝑛^2 𝑝 Γ— 𝑝^2 π‘š = π‘š^2x 𝑛 Γ— 𝑛^2 Γ— p Γ— 𝑝^2 Γ— π‘š = (π‘š^2 Γ— π‘š) Γ— (𝑛 Γ— 𝑛^2) Γ— (𝑝^2x 𝑝) = π‘š^3 Γ— 𝑛^3 Γ— 𝑝^3 = π’Ž^πŸ‘ 𝒏^πŸ‘ 𝒑^πŸ‘ Example 4 (iii) Find the volume of each rectangular box with given length, breadth and height. (iii) Length = πŸπ’’ , Breadth = γ€–πŸ’π’’γ€—^𝟐, Height = γ€–πŸ–π’’γ€—^πŸ‘ Volume = Length Γ— Breadth Γ— Height = 2π‘ž Γ— γ€–4π‘žγ€—^2 Γ— γ€–8π‘žγ€—^3 = 2 Γ— π‘ž Γ— 4 Γ— π‘ž^2 Γ— 8 Γ— π‘ž^3 = (2 Γ— 4 Γ— 8) Γ— (π‘ž Γ— π‘ž^2 Γ— π‘ž^3) = 64 Γ— π‘ž^6 = πŸ”πŸ’π’’^πŸ”

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.