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Example 9 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 2

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Transcript

Example 9 Multiply (ii) (π‘Ž^2+2𝑏^2 ) and (5π‘Žβˆ’3𝑏) (π‘Ž^2+2𝑏^2 )Γ—(5π‘Žβˆ’3𝑏) = π‘Ž^2 (5π‘Žβˆ’3𝑏)+2𝑏^2 (5π‘Žβˆ’3𝑏) = (π‘Ž^2Γ—5π‘Ž)βˆ’(π‘Ž^2Γ—3𝑏)+(2𝑏^2Γ—5π‘Ž)βˆ’(2𝑏^2Γ—3𝑏) = πŸ“π’‚^πŸ‘βˆ’πŸ‘π’‚^𝟐 𝒃+πŸπŸŽπ’ƒ^𝟐 π’‚βˆ’πŸ”π’ƒ^πŸ‘

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