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Last updated at Nov. 15, 2018 by Teachoo
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Ex 10.3, 12 How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively: (a) 100 cm and 144 cm Here, Number of tiles = (๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐๐๐๐๐๐)/(๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐ก๐๐๐) Finding area of rectangular region and rectangular tile Rectangular tile Length of tile = 12 cm Breadth of tile = 5 cm Area of tile = Length ร Breadth = 12 ร 5 = 60 sq. cm = 60 cm2 Rectangular region Length of region = 100 cm Breadth of region = 144cm Area of region = Length ร Breadth = 100 ร 144 = 14400 sq. cm = 14400 cm2 Number of tiles = (๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐๐๐๐๐๐)/(๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐ก๐๐๐๐ ) = 14400/60 = 1440/6 = 240 โด 240 tiles are required to cover the region Ex 10.3, 12 How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively: (b) 70 cm and 36 cm. Here, Number of tiles = (๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐๐๐๐๐๐)/(๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐ก๐๐๐) From part (a), Area of rectangular tile = 60 cm2 Finding area of rectangular region Rectangular region Length of rectangle = 70 cm Breadth of rectangle = 36 cm Area of rectangle = Length ร Breadth = 70 ร 36 = 2520 sq. cm = 2520 ใ๐๐ใ^2 Now, Number of tiles = (๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐๐๐๐๐๐)/(๐ด๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ข๐๐๐ ๐ก๐๐๐๐ ) = 2520/60 = 252/6 = 42 โด 42 tiles are required to cover the given region
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