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Ex 10.3
Ex 10.3, 1 (b) Important
Ex 10.3, 1 (c)
Ex 10.3, 1 (d) Important
Ex 10.3, 2 (a)
Ex 10.3, 2 (b) Important
Ex 10.3, 2 (c)
Ex 10.3, 3 Important
Ex 10.3, 4
Ex 10.3, 5 Important
Ex 10.3, 6
Ex 10.3, 7 Important
Ex 10.3, 8
Ex 10.3, 9 Important
Ex 10.3, 10 (a) Important
Ex 10.3, 10 (b)
Ex 10.3, 11 (a)
Ex 10.3, 11 (b) Important
Ex 10.3, 11 (c) Important
Ex 10.3, 12 (a) You are here
Ex 10.3, 12 (b) Important
Last updated at March 16, 2023 by Teachoo
Ex 10.3, 12 How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively: (a) 100 cm and 144 cm Here, Number of tiles = (π΄πππ ππ ππππ‘ππππ’πππ ππππππ)/(π΄πππ ππ ππππ‘ππππ’πππ π‘πππ) Finding area of rectangular region and rectangular tile Rectangular tile Length of tile = 12 cm Breadth of tile = 5 cm Area of tile = Length Γ Breadth = 12 Γ 5 = 60 sq. cm = 60 cm2 Rectangular region Length of region = 100 cm Breadth of region = 144cm Area of region = Length Γ Breadth = 100 Γ 144 = 14400 sq. cm = 14400 cm2 Number of tiles = (π΄πππ ππ ππππ‘ππππ’πππ ππππππ)/(π΄πππ ππ ππππ‘ππππ’πππ π‘ππππ ) = 14400/60 = 1440/6 = 240 β΄ 240 tiles are required to cover the region