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  1. Chapter 10 Class 6 Mensuration
  2. Serial order wise

Transcript

Ex 10.3, 11 (a) Split the following shapes into rectangles and find their areas. (The measures are given in centimeters) Our rectangles are: APEF, CDPB Rectangle APEF, Length = l = 2 cm Breadth = b = 12 cm Rectangle CDPB, Length = l = 8 cm Breadth = b = 2 cm Area = l × b = 2 × 12 = 24 sq. cm = 24 〖𝑐𝑚〗^2 Area = l × b = 8 × 2 = 16 sq. cm = 16 〖𝑐𝑚〗^2 Area of given shape = 24 + 16 = 40 sq. cm = 40 cm2 Ex 10.3, 11 (b) Split the following shapes into rectangles and find their areas. (The measures are given in centimeters) Our rectangles are: ABCL, KDEJ, IFGH Finding sides, CL In rectangle ABCL CL = AB CL = 7 cm (Opposite sides) KD KD = KL + CL + CD KD = 7 + 7 + 7 KD = 21 cm Rectangle ABCL, Length = l = 7 Breadth = b = 7 Area = l × b = 7 × 7 = 49 sq. unit Rectangle KDEJ, Length = l = 21 Breadth = b = 7 Area = l × b = 21 × 7 = 147 sq. unit Rectangle ABPJ, Length = l = 7 Breadth = b = 7 Area = l × b = 7 × 7 = 49 sq. unit Area of given shape = 49 + 147 + 49 = 245 cm2 Ex 10.3, 11 (c) Split the following shapes into rectangles and find their areas. (The measures are given in centimeters) Our rectangles are, ABCH, GDEF Rectangle ABCL, Length = l = 5 Breadth = b = 1 Rectangle GDEF, Length = l = 1 Breadth = b = 4 Area = l × b = 5 × 1 = 5 〖𝑐𝑚〗^2 Area = l × b = 1 × 4 = 5 〖𝑐𝑚〗^2 Area of given shape = 5 + 4 = 9 cm2

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.