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Ex 10.3, 1 - Chapter 10 Class 6 Mensuration - Part 4

Ex 10.3, 1 - Chapter 10 Class 6 Mensuration - Part 5
Ex 10.3, 1 - Chapter 10 Class 6 Mensuration - Part 6
Ex 10.3, 1 - Chapter 10 Class 6 Mensuration - Part 7

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Transcript

Ex 10.3, 1 (Method 1) Find the areas of the rectangles whose sides are : (d) 2 m and 70 cm Here, length & breadth are in different units So, we convert cm to m Length of rectangle = 2 m Breadth of rectangle = 70 cm = 70/100 m = 7/10 m (As 1 cm = 1/100 m) Area of rectangle = Length × Breadth = 2 × 7/10 = 14/10 = 1.4 sq. m = 1.4 m2 Ex 10.3, 1 (Method 2) Find the areas of the rectangles whose sides are : (d) 2 m and 70 cm Length = l = 2 m = 2 × 100 cm = 200 cm Breadth of b = 70 cm Area = l × b = 200 × 70 = 14000 cm2 (1 m = 100 cm) = 14000 × 1/10,000 m2 = 1.4 m2 1 cm = 1/100 m (1 cm)2 = (1/100 " m" )^2 ∴ 1 cm2 = 1/10000 m2

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