Ex 10.3, 1 (d) - Chapter 10 Class 6 Mensuration
Last updated at April 16, 2024 by Teachoo
Ex 10.3
Ex 10.3, 1 (b) Important
Ex 10.3, 1 (c)
Ex 10.3, 1 (d) Important You are here
Ex 10.3, 2 (a)
Ex 10.3, 2 (b) Important
Ex 10.3, 2 (c)
Ex 10.3, 3 Important
Ex 10.3, 4
Ex 10.3, 5 Important
Ex 10.3, 6
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Ex 10.3, 8
Ex 10.3, 9 Important
Ex 10.3, 10 (a) Important
Ex 10.3, 10 (b)
Ex 10.3, 11 (a)
Ex 10.3, 11 (b) Important
Ex 10.3, 11 (c) Important
Ex 10.3, 12 (a)
Ex 10.3, 12 (b) Important
Last updated at April 16, 2024 by Teachoo
Ex 10.3, 1 (Method 1) Find the areas of the rectangles whose sides are : (d) 2 m and 70 cm Here, length & breadth are in different units So, we convert cm to m Length of rectangle = 2 m Breadth of rectangle = 70 cm = 70/100 m = 7/10 m (As 1 cm = 1/100 m) Area of rectangle = Length × Breadth = 2 × 7/10 = 14/10 = 1.4 sq. m = 1.4 m2 Ex 10.3, 1 (Method 2) Find the areas of the rectangles whose sides are : (d) 2 m and 70 cm Length = l = 2 m = 2 × 100 cm = 200 cm Breadth of b = 70 cm Area = l × b = 200 × 70 = 14000 cm2 (1 m = 100 cm) = 14000 × 1/10,000 m2 = 1.4 m2 1 cm = 1/100 m (1 cm)2 = (1/100 " m" )^2 ∴ 1 cm2 = 1/10000 m2