Ex 10.3, 1 - Chapter 10 Class 6 Mensuration - Part 4

Ex 10.3, 1 - Chapter 10 Class 6 Mensuration - Part 5
Ex 10.3, 1 - Chapter 10 Class 6 Mensuration - Part 6
Ex 10.3, 1 - Chapter 10 Class 6 Mensuration - Part 7


Transcript

Ex 10.3, 1 (Method 1) Find the areas of the rectangles whose sides are : (d) 2 m and 70 cm Here, length & breadth are in different units So, we convert cm to m Length of rectangle = 2 m Breadth of rectangle = 70 cm = 70/100 m = 7/10 m (As 1 cm = 1/100 m) Area of rectangle = Length × Breadth = 2 × 7/10 = 14/10 = 1.4 sq. m = 1.4 m2 Ex 10.3, 1 (Method 2) Find the areas of the rectangles whose sides are : (d) 2 m and 70 cm Length = l = 2 m = 2 × 100 cm = 200 cm Breadth of b = 70 cm Area = l × b = 200 × 70 = 14000 cm2 (1 m = 100 cm) = 14000 × 1/10,000 m2 = 1.4 m2 1 cm = 1/100 m (1 cm)2 = (1/100 " m" )^2 ∴ 1 cm2 = 1/10000 m2

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.