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Ex 10.3

Ex 10.3, 1 (a)

Ex 10.3, 1 (b) Important

Ex 10.3, 1 (c)

Ex 10.3, 1 (d) Important

Ex 10.3, 2 (a)

Ex 10.3, 2 (b) Important

Ex 10.3, 2 (c)

Ex 10.3, 3 Important

Ex 10.3, 4

Ex 10.3, 5 Important

Ex 10.3, 6

Ex 10.3, 7 Important

Ex 10.3, 8

Ex 10.3, 9 Important

Ex 10.3, 10 (a) Important

Ex 10.3, 10 (b)

Ex 10.3, 11 (a)

Ex 10.3, 11 (b) Important

Ex 10.3, 11 (c) Important

Ex 10.3, 12 (a)

Ex 10.3, 12 (b) Important You are here

Last updated at Nov. 12, 2021 by Teachoo

Ex 10.3, 12 How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively: (b) 70 cm and 36 cm. Here, Number of tiles = (π΄πππ ππ ππππ‘ππππ’πππ ππππππ)/(π΄πππ ππ ππππ‘ππππ’πππ π‘πππ) From part (a), Area of rectangular tile = 60 cm2 Finding area of rectangular region Rectangular region Length of rectangle = 70 cm Breadth of rectangle = 36 cm Area of rectangle = Length Γ Breadth = 70 Γ 36 = 2520 sq. cm = 2520 γππγ^2 Now, Number of tiles = (π΄πππ ππ ππππ‘ππππ’πππ ππππππ)/(π΄πππ ππ ππππ‘ππππ’πππ π‘ππππ ) = 2520/60 = 252/6 = 42 β΄ 42 tiles are required to cover the given region