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Ex 10.3, 12 (b) - Chapter 10 Class 6 Mensuration

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Ex 10.3, 12 How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively: (b) 70 cm and 36 cm. Here, Number of tiles = (π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘Ÿπ‘’π‘π‘‘π‘Žπ‘›π‘”π‘’π‘™π‘Žπ‘Ÿ π‘Ÿπ‘’π‘”π‘–π‘œπ‘›)/(π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘Ÿπ‘’π‘π‘‘π‘Žπ‘›π‘”π‘’π‘™π‘Žπ‘Ÿ 𝑑𝑖𝑙𝑒) From part (a), Area of rectangular tile = 60 cm2 Finding area of rectangular region Rectangular region Length of rectangle = 70 cm Breadth of rectangle = 36 cm Area of rectangle = Length Γ— Breadth = 70 Γ— 36 = 2520 sq. cm = 2520 γ€–π‘π‘šγ€—^2 Now, Number of tiles = (π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘Ÿπ‘’π‘π‘‘π‘Žπ‘›π‘”π‘’π‘™π‘Žπ‘Ÿ π‘Ÿπ‘’π‘”π‘–π‘œπ‘›)/(π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘Ÿπ‘’π‘π‘‘π‘Žπ‘›π‘”π‘’π‘™π‘Žπ‘Ÿ 𝑑𝑖𝑙𝑒𝑠) = 2520/60 = 252/6 = 42 ∴ 42 tiles are required to cover the given region

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.