Ex 10.3, 10 (b) - Chapter 10 Class 6 Mensuration

Last updated at Dec. 16, 2024 by

Ex 10.3, 10 (b) - Chapter 10 Class 6 NCERT - By splitting the figure

Ex 10.3, 10 (b) - Chapter 10 Class 6 Mensuration - Part 2
Ex 10.3, 10 (b) - Chapter 10 Class 6 Mensuration - Part 3

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Ex 10.3, 10 (b) By splitting the following figures into rectangles, find their areas (The measures are given in centimeters). Our rectangles are ABCQ, QDEP, PFGH QD Finding sides, GH = QD + CD 3 = QD + 2 3 − 2 = QD 1 = QD QD = 1 AB By symmetry GH = AB 3 = AB AB = 3 Rectangle ABCQ Length = l = 1 Breadth = b = 3 Area = l × b = 1 × 3 = 3 cm2 Rectangle QDEP Length = l = 3 Breadth = b = 1 Area = l × b = 3 × 1 = 3 cm2 Rectangle PFGH Length = l = 1 Breadth = b = 3 Area = l × b = 1 × 3 = 3 cm2 Area of figure = 3 + 3 + 3 = 9 cm2

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