Ex 10.3, 10 (b) - Chapter 10 Class 6 Mensuration

Last updated at April 16, 2024 by

Ex 10.3, 10 (b) - Chapter 10 Class 6 NCERT - By splitting the figure

Ex 10.3, 10 (b) - Chapter 10 Class 6 Mensuration - Part 2
Ex 10.3, 10 (b) - Chapter 10 Class 6 Mensuration - Part 3

Transcript

Ex 10.3, 10 (b) By splitting the following figures into rectangles, find their areas (The measures are given in centimeters). Our rectangles are ABCQ, QDEP, PFGH QD Finding sides, GH = QD + CD 3 = QD + 2 3 − 2 = QD 1 = QD QD = 1 AB By symmetry GH = AB 3 = AB AB = 3 Rectangle ABCQ Length = l = 1 Breadth = b = 3 Area = l × b = 1 × 3 = 3 cm2 Rectangle QDEP Length = l = 3 Breadth = b = 1 Area = l × b = 3 × 1 = 3 cm2 Rectangle PFGH Length = l = 1 Breadth = b = 3 Area = l × b = 1 × 3 = 3 cm2 Area of figure = 3 + 3 + 3 = 9 cm2

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