Ex 10.3, 10 (b) - Chapter 10 Class 6 Mensuration
Last updated at April 16, 2024 by Teachoo
Ex 10.3
Ex 10.3, 1 (b) Important
Ex 10.3, 1 (c)
Ex 10.3, 1 (d) Important
Ex 10.3, 2 (a)
Ex 10.3, 2 (b) Important
Ex 10.3, 2 (c)
Ex 10.3, 3 Important
Ex 10.3, 4
Ex 10.3, 5 Important
Ex 10.3, 6
Ex 10.3, 7 Important
Ex 10.3, 8
Ex 10.3, 9 Important
Ex 10.3, 10 (a) Important
Ex 10.3, 10 (b) You are here
Ex 10.3, 11 (a)
Ex 10.3, 11 (b) Important
Ex 10.3, 11 (c) Important
Ex 10.3, 12 (a)
Ex 10.3, 12 (b) Important
Last updated at April 16, 2024 by Teachoo
Ex 10.3, 10 (b) By splitting the following figures into rectangles, find their areas (The measures are given in centimeters). Our rectangles are ABCQ, QDEP, PFGH QD Finding sides, GH = QD + CD 3 = QD + 2 3 − 2 = QD 1 = QD QD = 1 AB By symmetry GH = AB 3 = AB AB = 3 Rectangle ABCQ Length = l = 1 Breadth = b = 3 Area = l × b = 1 × 3 = 3 cm2 Rectangle QDEP Length = l = 3 Breadth = b = 1 Area = l × b = 3 × 1 = 3 cm2 Rectangle PFGH Length = l = 1 Breadth = b = 3 Area = l × b = 1 × 3 = 3 cm2 Area of figure = 3 + 3 + 3 = 9 cm2