# Ex 10.3, 8 - Chapter 10 Class 6 Mensuration

Last updated at Nov. 15, 2018 by Teachoo

Last updated at Nov. 15, 2018 by Teachoo

Transcript

Ex 10.3, 8 A floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted. Area of floor that is not carpeted = Area of rectangular carpeted − Area of square carpeted Rectangular Floor Length of floor = l = 5 m Breadth of floor = b = 4 m Area of floor = l × b = 5 × 4 = 20 sq. m = 20 m2 Square carpet Side of carpet = a = 3m Area of carpet = a × a = 3 × 3 = 9 sq. m = 9 m2 Now, Area of floor that is not carpeted = Area of rectangular carpeted − Area of square carpeted = 20 − 9 = 11 m2 ∴ 11 m2 of floor is not carpeted

Ex 10.3

Ex 10.3, 1 (a)

Ex 10.3, 1 (b)

Ex 10.3, 1 (c)

Ex 10.3, 1 (d)

Ex 10.3, 2 (a)

Ex 10.3, 2 (b)

Ex 10.3, 2 (c)

Ex 10.3, 3

Ex 10.3, 4

Ex 10.3, 5

Ex 10.3, 6

Ex 10.3, 7

Ex 10.3, 8 You are here

Ex 10.3, 9

Ex 10.3, 10 (a)

Ex 10.3, 10 (b)

Ex 10.3, 11 (a)

Ex 10.3, 11 (b)

Ex 10.3, 11 (c)

Ex 10.3, 12 (a)

Ex 10.3, 12 (b)

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.