Question 13 - Forming Linear Equations - Age - Chapter 2 Class 8 Linear Equations in One Variable

Last updated at April 16, 2024 by

Example 15 - Arjun is twice as old as Shriya. Five years ago his age

Example 15 - Chapter 2 Class 8 Linear Equations in One Variable - Part 2
Example 15 - Chapter 2 Class 8 Linear Equations in One Variable - Part 3

Transcript

Question 13 Arjun is twice as old as Shriya. Five years ago his age was three times Shriya s age. Find their present ages.Let Shriya s Present age be x years Arjun s present age = 2x years Five years ago, Shriya s age = (x 5) years Arjun s age = (2x 5) years Given, Five years ago Arjun s age = 3 Five years ago Shriya s age 2x 5 = 3 (x 5) 2x 5 = 3x 15 2x 5 + 15 = 3x 2x + 10 = 3x 3x = 2x + 10 3x 2x = 10 x = 10 Shreya's Present age = x = 10 years Arjun s present age = 2x = 2 10 = 20 years

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.