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  1. Chapter 2 Class 8 Linear Equations in One Variable
  2. Serial order wise
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Ex 2.3, 7 Solve the following equations and check your results. x = 4/5 (x + 10) ๐‘ฅ = 4/5 (๐‘ฅ+10) Multiplying both sides by 5 5๐‘ฅ=5ร—4/5 (๐‘ฅ+10) 5๐‘ฅ=4 (๐‘ฅ+10) 5๐‘ฅ=(4ร—๐‘ฅ)+(4ร—10) 5๐‘ฅ=4๐‘ฅ+40 5๐‘ฅโˆ’4๐‘ฅ=40 ๐’™=๐Ÿ’๐ŸŽ L.H.S x = 40 R.H.S 4/5 (๐‘ฅ+10) = 4/5 (40+10) = 4/5 ร—50=40 LHS = RHS Hence verified

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.