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  1. Chapter 2 Class 8 Linear Equations in One Variable
  2. Serial order wise
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Ex 2.3, 2 Solve the following equations and check your results. 5t – 3 = 3t – 55t − 3 = 3t − 5 5t = 3t − 5 + 3 5t = 3t − 2 5t − 3t = −2 2t = − 2 t = (−2)/2 t = −1 Check:- L.H.S 5t − 3 = 5 (−1) − 3 = −5 −3 = −8 R.H.S 3t − 5 = 3(−1) −5 = −3 − 5 = −8 ∴ LHS = RHS Hence Verified.

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.