Ex 2.2, 11 Baichung’s father is 26 years younger than Baichung’s grandfather & 29 years older than Baichung . The sum of the ages of all the three is 135 years. What is the age of each one of them?Let Baichung’s age be x years
Given that
Baichung’s father is 29 years older than Baichung
Baichung’s father age = (x + 29) years
Also,
Baichung’s father is 26 years younger than Baichung’s grandfather
Age of Baichung’s Father = Age of Baichung’s Grandfather – 26
Age of Baichung’s Father + 26 = Age of Baichung’s Grandfather
Age of Baichung’s Grandfather = Age of Baichung’s Father + 26
Age of Baichung’s Grandfather = (x + 29) + 26
= (x + 55) years
Given,
Sum of all ages is 135 years
x + (x + 29) + (x + 55) = 135
3x + 84 = 135
3x = 135 − 84
3x = 51
3x = 51
x = 51/3
x = 17
∴ Baichung’s age = x = 17 years
Baichung’s Father age = x + 29 = 17 + 29 = 46 years
Baichung’s Grandfather age = x + 55 = 17 + 55 = 72 years

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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