# Ex 2.2, 11 - Chapter 2 Class 8 Linear Equations in One Variable

Last updated at June 21, 2018 by Teachoo

Last updated at June 21, 2018 by Teachoo

Ex 2.2, 11 Baichung’s father is 26 years younger than Baichung’s grandfather & 29 years older than Baichung . The sum of the ages of all the three is 135 years. What is the age of each one of them?Let Baichung’s age be x years Given that Baichung’s father is 29 years older than Baichung Baichung’s father age = (x + 29) years Also, Baichung’s father is 26 years younger than Baichung’s grandfather Age of Baichung’s Father = Age of Baichung’s Grandfather – 26 Age of Baichung’s Father + 26 = Age of Baichung’s Grandfather Age of Baichung’s Grandfather = Age of Baichung’s Father + 26 Age of Baichung’s Grandfather = (x + 29) + 26 = (x + 55) years Given, Sum of all ages is 135 years x + (x + 29) + (x + 55) = 135 3x + 84 = 135 3x = 135 − 84 3x = 51 3x = 51 x = 51/3 x = 17 ∴ Baichung’s age = x = 17 years Baichung’s Father age = x + 29 = 17 + 29 = 46 years Baichung’s Grandfather age = x + 55 = 17 + 55 = 72 years