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  1. Chapter 2 Class 8 Linear Equations in One Variable
  2. Serial order wise
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Ex 2.2, 7 The sum of three consecutive multiples of 8 is 888. Find the multiples.Let first multiple = x Second multiple = x + 8 Third multiple = (x + 8) + 8 = x + 16 Given, Sum of multiples = 888 x + (x + 8) + (x + 16) = 888 x + x + x + 8 + 16 = 888 3x + 24 = 888 3x = 888 − 24 Rough Multiple of 8 are 8, 16, 24, 32,.. Consecutive Multiple are 8, 16, 24 Difference Between two Multiples = 8 If 1st multiple is 8 then 2nd multiple = 8 + 8 = 16 3rd multiple = 16 + 8 = 24 3x = 864 x = (864 )/3 x = 288 Thus, ∴ First multiple = x = 288 Second multiple = x + 8 = 288 + 8 = 296 Third multiple = x + 16 = 288 + 16 = 304

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.