Suppose angle of elevation from point A to the top of the tower is 45°. And distance from point A to the bottom of tower is 10m.

What is the height of the tower?

 

Let building be BC

How to find Height when angle of elevation is given.jpg

 

So, ∠ BAC = 45°

and AC = 10 m

 

Now, we need to find height of tower i.e. BC

And we are given base 10 m.

So, we can use tan

As

tan A = Side opposite to angle A / Side adjacent to angle A

tan 45° = BC / AC

1 = BC/ 10

1 × 10 = BC

10 = BC

BC = 10 m

 

∴ Height of tower is 10 m

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.