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Suppose angle of elevation from point A to the top of the tower is 45°. And distance from point A to the bottom of tower is 10m.

What is the height of the tower?


Let building be BC

How to find Height when angle of elevation is given.jpg


So, ∠ BAC = 45°

and AC = 10 m


Now, we need to find height of tower i.e. BC

And we are given base 10 m.

So, we can use tan


tan A = Side opposite to angle A / Side adjacent to angle A

tan 45° = BC / AC

1 = BC/ 10

1 × 10 = BC

10 = BC

BC = 10 m


∴ Height of tower is 10 m

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.