Learn all Concepts of Chapter 9 Class 10 (with VIDEOS). Check - Heights and Distances - Class 10

Suppose angle of elevation from point A to the top of the tower is 45°. And distance from point A to the bottom of tower is 10m.

What is the height of the tower?

Let building be BC

So, ∠ BAC = 45°

and AC = 10 m

Now, we need to find height of tower i.e. BC

And we are given base 10 m.

So, we can use tan

As

tan A = Side opposite to angle A / Side adjacent to angle A

tan 45° = BC / AC

1 = BC/ 10

1 × 10 = BC

10 = BC

BC = 10 m

∴ Height of tower is 10 m