Ex 9.1, 16 - Chapter 9 Class 10 Some Applications of Trigonometry (Term 2)
Last updated at Dec. 24, 2019 by Teachoo
Last updated at Dec. 24, 2019 by Teachoo
Transcript
Ex 9.1, 16 The angles of elevation of the top of a tower from two points at a distance of 4 m and 9 m from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6 m. Given that AB is the tower P, Q are the point at distance 4m and 9m resp. Also, PB = 4m , QB = 9m & Angle of elevation from P is 𝛼 Angle of elevation from Q is 𝛽. Given 𝛼 and 𝛽 are supplementary. 𝛼 + 𝛽 = 90° We need to prove AB = 6m From (1) and (2) ABBP = BQAB AB × AB = BQ × BP (AB)2= 4 × 9 (AB)2= 36 AB = 36 12 AB = 6m Hence, height of the tower is 6m. Hence proved
Questions easy to difficult
Angle of Depression from point A to point B is same as Angle of Elevation from point B to point A
How to find Height when angle of elevation is given?
How to find Distance when angle of depression is given?
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Ex 9.1, 16 Important You are here
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