Ex 9.1 , 2
A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle 30° with it. The distance between the foot of the tree to the point where the top touches the ground is 8 m. Find the height of the tree.
Let, the broken part of tree be AC
It is given that,
Distance between foot of the tree B and point C = 8m
So, BC = 8m
Also, broken parts of tree makes an angle 30° with ground
So, ∠C = 30°
We need to find height of tree
Height of tree = Height of broken part + height of remaining tree
Height of tree = AB + AC
Since,
Tree was vertical to ground
So, ∠ ABC = 90°
So,
Height of tree = AC + AB
= 16/√3 + 8/√3
= 24/√3
Multiplying √3 in numerator and denominator
= 24/√3 × √3/√3
= 24 × √3/3
= 8√3
Hence, height of tree is 8√3 m
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo
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