**Ex 11.2, 5**

Construct a Right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm.

Let triangle be Δ ABC

Given base BC = 12 cm,

∠ B = 90°

and AB + BC = 18 cm.

__Steps of construction__

- Draw base BC = 7 cm and at point B make an ∠ XBC = ∠ B = 75°
- Cut a line segment BD equal to AB + AC from ray BX.
- Join DC. Draw perpendicular bisector PQ of line DC.
- Let PQ intersect BD a point A. Join AC.

Then, Δ ABC is the required triangle.