Construct a Right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm.
Let triangle be Δ ABC
Given base BC = 12 cm,
∠ B = 90°
and AB + BC = 18 cm.
Steps of construction
Draw base BC = 7 cm and at point B make an ∠ XBC = ∠ B = 75°
Cut a line segment BD equal to AB + AC from ray BX.
Join DC. Draw perpendicular bisector PQ of line DC.
Let PQ intersect BD a point A. Join AC.
Then, Δ ABC is the required triangle.
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.