Question 5 - Chapter 11 Class 9 Constructions (Important Question)

Last updated at July 24, 2026 by

Ex 11.2, 5 - Construct a right triangle whose base is 12cm and sum

Ex 11.2, 5 - Chapter 11 Class 9 Constructions - Part 2
Ex 11.2, 5 - Chapter 11 Class 9 Constructions - Part 3 Ex 11.2, 5 - Chapter 11 Class 9 Constructions - Part 4

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Question 5 Construct a Right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm. Let Δ ABC be the right angled triangle where BC = 12 cm, ∠ B = 90° and AC + AB = 18 cm Steps of Construction: Draw base BC of length 12 cm 2. Now, let’s draw ∠ B = 90° Let the ray be BX Check Ex 11.1, 1 on how to construct 90° 3. Open the compass to length AB + AC = 18 cm. From point B as center, cut an arc on ray BX. Let the arc intersect BX at D 4. Join CD Now, we will draw perpendicular bisector of CD 6. Mark point A where perpendicular bisector intersects BD Join AC ∴ Δ ABC is the required triangle

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