Ex 6.1, 18 - Total revenue is given by R(x) = 3x^2 + 36x + 5. Marginal

Ex 6.1, 18 - Chapter 6 Class 12 Application of Derivatives - Part 2
Ex 6.1, 18 - Chapter 6 Class 12 Application of Derivatives - Part 3

  1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise

Transcript

Ex 6.1, 18 The total revenue in Rupees received from the sale of ๐‘ฅ units of a product is given by R(๐‘ฅ) = 3๐‘ฅ2 + 36๐‘ฅ + 5. The marginal revenue, when ๐‘ฅ = 15 is (A) 116 (B) 96 (C) 90 (D) 126Marginal revenue is rate of change of total revenue w. r. t the number of unit sold Let MR be marginal revenue So, MR = ๐’…๐‘น/๐’…๐’™ Given, Total revenue = R (๐‘ฅ) = 3๐‘ฅ2 + 36๐‘ฅ + 5 We need to find marginal revenue when ๐‘ฅ = 15 i.e. MR when ๐‘ฅ = 15 MR = ๐‘‘(๐‘…(๐‘ฅ))/๐‘‘๐‘ฅ MR = (๐‘‘ (3๐‘ฅ2 + 36๐‘ฅ + 5) )/๐‘‘๐‘ฅ MR = (๐‘‘(3๐‘ฅ2))/๐‘‘๐‘ฅ + (๐‘‘(36๐‘ฅ))/๐‘‘๐‘ฅ + (๐‘‘(5))/๐‘‘๐‘ฅ MR = 3 (๐‘‘(๐‘ฅ2))/๐‘‘๐‘ฅ + 36 (๐‘‘(๐‘ฅ))/๐‘‘๐‘ฅ + 0 MR = 3 ร— 2๐‘ฅ + 36 MR = 6๐’™ + 36 MR when ๐’™ = 15 MR = 6(15) + 36 MR = 90 + 36 MR = 126 Hence, the required marginal revenue is Rs. 126 Thus, D is the correct Answer

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.