# Ex 6.1,18 - Chapter 6 Class 12 Application of Derivatives

Last updated at Dec. 8, 2016 by Teachoo

Last updated at Dec. 8, 2016 by Teachoo

Transcript

Ex 6.1,18 The total revenue in Rupees received from the sale of ð¥ units of a product is given by R(ð¥) = 3ð¥2 + 36ð¥ + 5. The marginal revenue, when ð¥ = 15 is (A) 116 (B) 96 (C) 90 (D) 126 Since Marginal Revenue is Rate of change in total Revenue w.r.t no of unit sold Let MR = Marginal cost R ð¥ï·¯= Total Revenue ð¥= no. of unit sold So, MR = ð ð ð¥ï·¯ï·¯ï·®ðð¥ï·¯ It is Given that R ð¥ï·¯=3 ð¥ï·®2ï·¯+36ð¥+15 We need to find marginal Revenue when ð¥ = 15 i.e. MR at ð¥ = 15 MR = ð ð ð¥ï·¯ï·¯ï·®ðð¥ï·¯ MR = ð 3 ð¥ï·®2ï·¯+36ð¥+5ï·¯ï·®ðð¥ï·¯ MR = ð 3 ð¥ï·®2ï·¯ï·¯ï·®ðð¥ï·¯+ ð 36ð¥ï·¯ï·®ðð¥ï·¯+ ð 5ï·¯ï·®ðð¥ï·¯ MR = 3 ð ð¥ï·®2ï·¯ï·¯ï·®ðð¥ï·¯+36 ð ð¥ï·¯ï·®ðð¥ï·¯+0 MR = 3 Ã2ð¥+36 MR = 6ð¥+36 MR when ð¥ = 15 MR = 6 15ï·¯+36 MR = 90 + 36 MR = 126 Hence Marginal Revenue is Rs. 126 Thus, D is the correct Answer

Chapter 6 Class 12 Application of Derivatives

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.