Ex 6.1, 18 (MCQ) - Chapter 6 Class 12 Application of Derivatives (Term 1)

Last updated at Aug. 19, 2021 by Teachoo

Transcript

Ex 6.1, 18 The total revenue in Rupees received from the sale of 𝑥 units of a product is given by R(𝑥) = 3𝑥2 + 36𝑥 + 5. The marginal revenue, when 𝑥 = 15 is (A) 116 (B) 96 (C) 90 (D) 126Marginal revenue is rate of change of total revenue w. r. t the number of unit sold
Let MR be marginal revenue
So, MR = 𝒅𝑹/𝒅𝒙
Given,
Total revenue = R (𝑥) = 3𝑥2 + 36𝑥 + 5
We need to find marginal revenue when 𝑥 = 15
i.e. MR when 𝑥 = 15
MR = 𝑑(𝑅(𝑥))/𝑑𝑥
MR = (𝑑 (3𝑥2 + 36𝑥 + 5) )/𝑑𝑥
MR = (𝑑(3𝑥2))/𝑑𝑥 + (𝑑(36𝑥))/𝑑𝑥 + (𝑑(5))/𝑑𝑥
MR = 3 (𝑑(𝑥2))/𝑑𝑥 + 36 (𝑑(𝑥))/𝑑𝑥 + 0
MR = 3 × 2𝑥 + 36
MR = 6𝒙 + 36
MR when 𝒙 = 15
MR = 6(15) + 36
MR = 90 + 36
MR = 126
Hence, the required marginal revenue is Rs. 126
Thus, D is the correct Answer

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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