# Ex 6.1, 18 - Chapter 6 Class 12 Application of Derivatives

Last updated at Jan. 7, 2020 by Teachoo

Last updated at Jan. 7, 2020 by Teachoo

Transcript

Ex 6.1,18 The total revenue in Rupees received from the sale of ๐ฅ units of a product is given by R(๐ฅ) = 3๐ฅ2 + 36๐ฅ + 5. The marginal revenue, when ๐ฅ = 15 is (A) 116 (B) 96 (C) 90 (D) 126 Since Marginal Revenue is Rate of change in Total Revenue w.r.t no of unit sold Let MR = Marginal cost R(๐ฅ)= Total Revenue ๐ฅ= no. of unit sold So, MR = ๐(๐ (๐ฅ))/๐๐ฅ โฆ(1) It is Given that R(๐ฅ)=3๐ฅ^2+36๐ฅ+15 We need to find marginal Revenue when ๐ฅ = 15 i.e. MR at ๐ฅ = 15 MR = ๐(๐ (๐ฅ))/๐๐ฅ MR = ๐(3๐ฅ^2 + 36๐ฅ + 5)/๐๐ฅ MR = ๐(3๐ฅ^2 )/๐๐ฅ+๐(36๐ฅ)/๐๐ฅ+๐(5)/๐๐ฅ MR = 3 ๐(๐ฅ^2 )/๐๐ฅ+36 ๐(๐ฅ)/๐๐ฅ+0 MR = 3 ร 2๐ฅ+36 MR = 6๐ฅ+36 MR when ๐ = 15 MR = 6(15)+36 MR = 90 + 36 MR = 126 Hence Marginal Revenue is Rs. 126 Thus, D is the correct Answer

Chapter 6 Class 12 Application of Derivatives

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