Ex 6.1

Ex 6.1, 1
Deleted for CBSE Board 2022 Exams

Ex 6.1,2 Deleted for CBSE Board 2022 Exams

Ex 6.1,3 Deleted for CBSE Board 2022 Exams

Ex 6.1,4 Important Deleted for CBSE Board 2022 Exams You are here

Ex 6.1,5 Important Deleted for CBSE Board 2022 Exams

Ex 6.1,6 Deleted for CBSE Board 2022 Exams

Ex 6.1,7 Deleted for CBSE Board 2022 Exams

Ex 6.1,8 Deleted for CBSE Board 2022 Exams

Ex 6.1,9 Deleted for CBSE Board 2022 Exams

Ex 6.1,10 Important Deleted for CBSE Board 2022 Exams

Ex 6.1,11 Important Deleted for CBSE Board 2022 Exams

Ex 6.1,12 Deleted for CBSE Board 2022 Exams

Ex 6.1,13 Important Deleted for CBSE Board 2022 Exams

Ex 6.1,14 Deleted for CBSE Board 2022 Exams

Ex 6.1,15 Important Deleted for CBSE Board 2022 Exams

Ex 6.1,16 Deleted for CBSE Board 2022 Exams

Ex 6.1,17 (MCQ) Deleted for CBSE Board 2022 Exams

Ex 6.1, 18 (MCQ) Important Deleted for CBSE Board 2022 Exams

Last updated at April 19, 2021 by Teachoo

Ex 6.1, 4 An edge of a variable cube is increasing at the rate of 3 cm/s. How fast is the volume of cube increasing when the edge is 10 cm long?Let ๐ be the edge of cube. & V be the volume of cube. Given that Edge of cube is increasing at the rate of 3 cm/ sec โด ๐ ๐/๐ ๐ = 3 cm/sec We need to calculate how fast volume of cube increasing when edge is 10 cm i.e. we need to find ๐ ๐ฝ/๐ ๐ when ๐ฅ = 10 cm We know that Volume of cube = (Edge)3 V = ๐ฅ3 Differentiate w.r.t time ๐ ๐ฝ/๐ ๐ = (๐ (๐๐))/๐ ๐ ๐๐/๐๐ก = (๐(๐ฅ3))/๐๐ก ร ๐๐ฅ/๐๐ฅ ๐๐/๐๐ก = (๐(๐ฅ3))/๐๐ฅ ร ๐๐ฅ/๐๐ก ๐๐/๐๐ก = 3๐ฅ2 . ๐ ๐/๐ ๐ ๐๐/๐๐ก = 3๐ฅ2 ร 3 ๐๐/๐๐ก = 9๐ฅ2 When ๐ฅ = 10 โ ๐๐/๐๐กโค|_(๐ฅ =10) = 9(10)2 โ ๐๐/๐๐กโค|_(๐ฅ =10) = 900 Since value is in cm3 & time is in sec ๐ ๐ฝ/๐ ๐ = 900 cm3/sec Hence, volume of a cube is increasing at the rate of 900 cm3/sec