Ex 6.1

Ex 6.1, 1
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Ex 6.1,2 Deleted for CBSE Board 2022 Exams

Ex 6.1,3 Deleted for CBSE Board 2022 Exams

Ex 6.1,4 Important Deleted for CBSE Board 2022 Exams

Ex 6.1,5 Important Deleted for CBSE Board 2022 Exams

Ex 6.1,6 Deleted for CBSE Board 2022 Exams

Ex 6.1,7 Deleted for CBSE Board 2022 Exams

Ex 6.1,8 Deleted for CBSE Board 2022 Exams

Ex 6.1,9 Deleted for CBSE Board 2022 Exams

Ex 6.1,10 Important Deleted for CBSE Board 2022 Exams

Ex 6.1,11 Important Deleted for CBSE Board 2022 Exams

Ex 6.1,12 Deleted for CBSE Board 2022 Exams

Ex 6.1,13 Important Deleted for CBSE Board 2022 Exams

Ex 6.1,14 Deleted for CBSE Board 2022 Exams

Ex 6.1,15 Important Deleted for CBSE Board 2022 Exams You are here

Ex 6.1,16 Deleted for CBSE Board 2022 Exams

Ex 6.1,17 (MCQ) Deleted for CBSE Board 2022 Exams

Ex 6.1, 18 (MCQ) Important Deleted for CBSE Board 2022 Exams

Last updated at April 19, 2021 by Teachoo

Ex 6.1, 15 The total cost C(𝑥) in Rupees associated with the production of 𝑥 units of an item is given by 𝐶(𝑥) = 0.007𝑥^3 – 0.003𝑥2 + 15𝑥 + 4000. Find the marginal cost when 17 units are produced.Since Marginal Cost is Rate of change in Total Cost w.r.t No of units produced Let MC be marginal cost So, MC = 𝒅𝑪/𝒅𝒙 Given, Total Cost = C(𝑥) =0.007𝑥^3−0.003𝑥^2+15𝑥+4000" " We need to find marginal Cost when 17 units are produced i.e. MC when 𝑥 = 17 MC = 𝑑(𝐶(𝑥))/𝑑𝑥 MC = 𝑑(0.007𝑥^3 − 0.003𝑥^2 + 15𝑥 + 4000)/𝑑𝑥 MC = 𝑑(0.007𝑥^3 )/𝑑𝑥 − 𝑑(0.003𝑥^2 )/𝑑𝑥+ 𝑑(15𝑥)/𝑑𝑥+ 𝑑(4000)/𝑑𝑥 MC = 0.007 𝑑(𝑥^3 )/𝑑𝑥 −0.003 𝑑(𝑥^2 )/𝑑𝑥 + 15𝑑(𝑥)/𝑑𝑥+0 MC = 0.007 × 3𝑥^2−0.003 ×2𝑥+15 MC = 0.021𝑥^2−0.006𝑥+15 We need to find MC when 𝑥=17 Putting 𝒙=𝟏𝟕 MC = 0.021(17)^2−0.006(17)+15 MC = 6.069 – 0.102 + 15 MC = 20.967 Hence, the Required Marginal cost is Rs. 20.967