1 Theorem 7.4 - PQR = WYZ (SAS congruency) THUS W = P.jpg

Theorem 7.4 - Chapter 7 Class 9 Triangles - Part 2
Theorem 7.4 - Chapter 7 Class 9 Triangles - Part 3
Theorem 7.4 - Chapter 7 Class 9 Triangles - Part 4

  1. Chapter 7 Class 9 Triangles (Term 1)
  2. Serial order wise

Transcript

Theorem 7.4 (SSS congruence rule) If three sides of a triangle are equal to the three sides of another triangle, then the two triangles are congruent) Given :- PQR & XYZ such that PQ = XY , QR = YZ , PR = XZ To Prove :- PQR XYZ Construction:- Draw XW intersecting YZ such that WYZ = PQR and WY = PQ. Also, Join WZ Proof:- In PQR and WYZ PQ = WY PQR = WYZ QR = YZ PQR WYZ Thus, W = P In XYW Since PQ = WY and PQ = XY WY = XY 1 = 2 Similarly, we can prove 3 = 4 Adding (2) and (3) we get 1 + 3 = 2 + 4 X = W X = W From (1), W = P P = X Now in PQR and XYZ PQ = XY P = X PR = XZ PQR WYZ Hence Proved.

About the Author

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.