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Theorem 7.2 - Angle opposite to equal sides of an isosceles triangle.jpg

Theorem 7.2 - Chapter 7 Class 9 Triangles - Part 2


Transcript

Theorem 7.2 :- Angle opposite to equal sides of an isosceles triangle are equal. Given :- Isosceles triangle ABC i.e. AB = AC To Prove :- ∠B = ∠C Construction:- Draw a bisector of ∠A intersecting BC at D. Proof:- In △BAD and △CAD AB = AC ∠BAD = ∠CAD AD = AD △BAD ≅ △CAD Thus, ∠ABD = ∠ACD ⇒ ∠B = ∠C Hence, angles opposite to equal sides are equal. Hence proved

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.