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Last updated at May 29, 2018 by Teachoo

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Ex 13.5, 8 Suppose X has a binomial distribution B (6, 12) . Show that X = 3 is the most likely outcome. (Hint : P(X = 3) is the maximum among all P(xi), xi = 0,1,2,3,4,5,6) B(6, 12) means Here , n = 6, p = 𝟏𝟐 So , q = 1 − 12 = 12 Hence, P (X = x) = 6Cx 12𝑥 126−𝑥 P (X = x) = 6Cx 12𝑥 + 6 − 𝑥 P (X = x) = 6Cx 𝟏𝟐𝒙 Hence, P (X = x) = 6Cx 12𝑥 We need to show that X = 3 is the most likely outcome. i.e. P(X = 3) is the maximum among P(X = 0) , P(X = 1), P(X = 2), P(X = 3), P(X = 4), P(X = 5), P(X = 6) Since P(X = 3) is maximum ∴ Most likely outcome is X = 3

Ex 13.5

Ex 13.5, 1
Not in Syllabus - CBSE Exams 2021

Ex 13.5, 2 Not in Syllabus - CBSE Exams 2021

Ex 13.5, 3 Important Not in Syllabus - CBSE Exams 2021

Ex 13.5, 4 Important Not in Syllabus - CBSE Exams 2021

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Ex 13.5, 8 Not in Syllabus - CBSE Exams 2021 You are here

Ex 13.5, 9 Not in Syllabus - CBSE Exams 2021

Ex 13.5, 10 Important Not in Syllabus - CBSE Exams 2021

Ex 13.5, 11 Not in Syllabus - CBSE Exams 2021

Ex 13.5, 12 Not in Syllabus - CBSE Exams 2021

Ex 13.5, 13 Important Not in Syllabus - CBSE Exams 2021

Ex 13.5, 14 Important Not in Syllabus - CBSE Exams 2021

Ex 13.5, 15 Important Not in Syllabus - CBSE Exams 2021

Chapter 13 Class 12 Probability

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.