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  1. Chapter 13 Class 12 Probability
  2. Serial order wise

Transcript

Ex 13.5, 7 In an examination, 20 questions of true-false type are asked. Suppose a student tosses a fair coin to determine his answer to each question. If the coin falls heads, he answers 'true'; if it falls tails, he answers 'false'. Find the probability that he answers at least 12 questions correctly.Let X : be the number of questions he answers correctly Tossing a coin is a Bernoulli trial So, X has binomial distribution P(X = x) = nCx ๐’’^(๐’โˆ’๐’™) ๐’‘^๐’™ Here, n = number of questions = 20 p = Probability of getting answer correct Since it is a true false question P(he answers correctly) = p = 1/2 Thus, q = 1 โ€“ p = 1 โ€“ 1/2 = 1/2 Hence, P(X = x) = 20Cx (1/2)^๐‘ฅ (1/2)^(20โˆ’๐‘ฅ) P(X = x) = 20Cx (1/2)^(20 โˆ’ ๐‘ฅ + ๐‘ฅ) P(X = x) = 20Cx (๐Ÿ/๐Ÿ)^๐Ÿ๐ŸŽ We need to find probability that he answers at least 12 questions correctly i.e. P(X โ‰ฅ 12) P(X โ‰ฅ 12) = P(12) + P(13) + P(14) + โ€ฆโ€ฆ โ€ฆ.. +P(20) = 20C12 (1/2)^20 + 20C13 (1/2)^20+ 20C14 (1/2)^20+ โ€ฆโ€ฆ + 20C20 (1/2)^20 = (๐Ÿ/๐Ÿ)^๐Ÿ๐ŸŽ(20C12 + 20C13 + 20C14 + โ€ฆโ€ฆ.. + 20C20)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.