Question 4 - Bernoulli Trial - Chapter 13 Class 12 Probability
Last updated at April 16, 2024 by Teachoo
Bernoulli Trial
Question 2 Deleted for CBSE Board 2025 Exams
Question 3 Important Deleted for CBSE Board 2025 Exams
Question 4 Important Deleted for CBSE Board 2025 Exams You are here
Question 5 Deleted for CBSE Board 2025 Exams
Question 6 Important Deleted for CBSE Board 2025 Exams
Question 7 Important Deleted for CBSE Board 2025 Exams
Question 8 Deleted for CBSE Board 2025 Exams
Question 9 Deleted for CBSE Board 2025 Exams
Question 10 Important Deleted for CBSE Board 2025 Exams
Question 11 Deleted for CBSE Board 2025 Exams
Question 12 Deleted for CBSE Board 2025 Exams
Question 13 Important Deleted for CBSE Board 2025 Exams
Question 14 (MCQ) Important Deleted for CBSE Board 2025 Exams
Question 15 (MCQ) Important Deleted for CBSE Board 2025 Exams
Last updated at April 16, 2024 by Teachoo
Question 4 Five cards are drawn successively with replacement from a well-shuffled deck of 52 cards. What is the probability that (i) all the five cards are spades? (ii) only 3 cards are spades? (iii) none is a spade?Let X : be the number of spade cards Drawing a card is a Bernoulli trial So, X has binomial distribution P(X = x) = nCx 𝒒^(𝒏−𝒙) 𝒑^𝒙 Here, n = number of cards drawn = 5 p = Probability of getting spade card = 13/52=1/4 q = 1 – p = 1 – 1/4=3/4 Hence, P(X = x) = 5Cx (𝟑/𝟒)^(𝟓−𝒙) (𝟏/𝟒)^𝒙 P(all cards are spade) = 5𝐶5(1/4)^5 (3/4)^0 = (1/4)^5 =𝟏/𝟏𝟎𝟐𝟒 P(only three cards are spade) = 5𝐶3(1/4)^3 (3/4)^2 = 5!/(3! 2!) × 9/1024 =𝟒𝟓/𝟓𝟏𝟐 (iii) P(none of them are spade) = 5𝐶0(1/4)^0 (3/4)^5 = (3/4)^5 = 𝟐𝟒𝟑/𝟏𝟎𝟐𝟒