Check sibling questions

Ex 1.2, 4 - Show that Modulus Function f(x) = |x| is neither - To prove injective/ surjective/ bijective (one-one & onto)

Ex 1.2 , 4 - Chapter 1 Class 12 Relation and Functions - Part 2

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Ex 1.2 , 4 Show that the Modulus Function f: R R given by f(x) = , is neither one-one nor onto, where is x, if x is positive or 0 and is x, if x is negative. f(x) = = , 0 , <0 Check one-one For example: f (1) = 1 = 1 f ( 1) = 1 = 1 Check onto f: R R f(x) = Let f(x) = y such that y R y = Hence value of y is defined only if y is positive, But y is a real number Hence, if y is negative, there is not corresponding element of x Hence, f is not onto

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.