Ex 5.1, 31 - Ex 5.1

Ex 5.1, 31 - Chapter 5 Class 12 Continuity and Differentiability - Part 2

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Ex 5.1, 31 Show that the function defined by ๐‘“(๐‘ฅ)=cosโก(๐‘ฅ^2 ) is a continuous function.๐‘“(๐‘ฅ) = cosโก(๐‘ฅ^2 ) Let ๐’ˆ(๐’™) = cosโก๐‘ฅ & ๐’‰(๐’™) = ๐‘ฅ^2 Now, ๐’ˆ๐’๐’‰(๐’™) = g(โ„Ž(๐‘ฅ)) = ๐‘”(๐‘ฅ^2 ) = cosโก(๐‘ฅ^2 ) = ๐’‡(๐’™) Hence, ๐‘“(๐‘ฅ) = ๐‘”๐‘œโ„Ž(๐‘ฅ) We know that ๐’ˆ(๐’™) = cosโก๐‘ฅ is continuous as cos x is always continuous & ๐’‰(๐’™) = ๐‘ฅ^2 is continuous as it is a polynomial Hence, ๐‘”(๐‘ฅ) & โ„Ž(๐‘ฅ) are both continuous . We know that If two function of ๐‘”(๐‘ฅ) & โ„Ž(๐‘ฅ) both continuous, then their composition ๐’ˆ๐’๐’‰(๐’™) is also continuous Hence, ๐’‡(๐’™) is continuous .

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