Question 1 - Show that line joining origin to the point (2, 1, 1) is - Miscellaneous

part 2 - Question 1 - Miscellaneous - Serial order wise - Chapter 11 Class 12 Three Dimensional Geometry

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Question 1 Show that the line joining the origin to the point (2, 1, 1) is perpendicular to line determined by the points (3, 5, โ€“ 1), (4, 3, โ€“1).Two lines having direction ratios ๐‘Ž1, ๐‘1 , ๐‘1 and ๐‘Ž2, ๐‘2, ๐‘2 are Perpendicular to each other if ๐’‚1 ๐’‚2 + ๐’ƒ1 ๐’ƒ2 + ๐’„1 ๐’„2 = 0 Also, a line passing through (x1, y1, z1) and (x2, y2, z2) has the direction ratios (x2 โˆ’ x1), (y2 โˆ’ y1), (z2 โˆ’ z1) We have two lines here: Line joining Origin O (0, 0, 0) and point A (2, 1, 1) Line joining points B (3, 5, -1) and C (4, 3, โˆ’1) Finding Direction ratios of both lines Line O (0, 0, 0) & A (2, 1, 1) Direction ratios : = (2 โˆ’ 0), (1 โˆ’ 0), (1 โˆ’ 0) = 2, 1, 1 โˆด ๐’‚1 = 2, ๐’ƒ1 = 1, ๐’„1 = 1 Line B (3, 5, โˆ’1) & C (4, 3, โˆ’1) Direction ratios: = (4 โˆ’ 3), (3 โˆ’ 5), ( โˆ’1 + 1) = 1, โˆ’2, 0 โˆด ๐’‚2 = 1, ๐’ƒ2 = โˆ’2, ๐’„2 = 0 Now, ๐’‚1 ๐’‚2 + ๐’ƒ1 ๐’ƒ2 + ๐’„1 ๐’„2 = (2 ร— 1) + (1 ร— โˆ’2) + (1 ร— 0) = 2 + (โˆ’2) + 0 = 2 โˆ’ 2 = 0 Therefore, the given two lines are perpendicular

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