Ex 11.2, 2 - Show line (1, -1, 2), (3, 4, -2) is perpendicular - Ex 11.2

part 2 - Ex 11.2, 2 - Ex 11.2 - Serial order wise - Chapter 11 Class 12 Three Dimensional Geometry

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Transcript

Ex 11.2, 2 Show that the line through the points (1, โˆ’1, 2), (3, 4, โˆ’2) is perpendicular to the line through the points (0, 3, 2) and (3, 5, 6). Two lines with direction ratios ๐‘Ž1, ๐‘1, ๐‘1 and ๐‘Ž2, ๐‘2, ๐‘2 are perpendicular to each other if ๐’‚๐Ÿ ๐’‚๐Ÿ + ๐’ƒ๐Ÿ ๐’ƒ๐Ÿ + ๐’„๐Ÿ ๐’„๐Ÿ = 0 Now, a line passing through (x1, y1, z1) and (x2, y2, z2) has the direction ratios (x2 โˆ’ x1), (y2 โˆ’ y1), (z2 โˆ’ z1) A (1, โˆ’1, 2) B (3, 4, โˆ’2) Direction ratios (3 โˆ’ 1), 4 โˆ’ (โˆ’1), โˆ’2 โˆ’ 2 = 2, 5, โ€“4 โˆด ๐’‚๐Ÿ = 2, ๐’ƒ๐Ÿ = 5, ๐’„๐Ÿ = โˆ’4 C (0, 3, 2) D (3, 5, 6) Direction ratios (3 โˆ’ 0), (5 โˆ’ 3), (6 โˆ’ 2) = 3, 2, 4 โˆด ๐’‚๐Ÿ = 3, ๐’ƒ๐Ÿ = 2, ๐’„๐Ÿ = 4 Now, ๐’‚๐Ÿ ๐’‚๐Ÿ + ๐’ƒ๐Ÿ ๐’ƒ๐Ÿ + ๐’„๐Ÿ ๐’„๐Ÿ = (2 ร— 3) + (5 ร— 2) + (โˆ’4 ร— 4) = 6 + 10 + (โˆ’16) = 16 โˆ’ 16 = 0 Therefore the given two lines are perpendicular.

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