Ex 10.2, 14 - Show that i + j + k is equally inclined to OX, OY

Ex 10.2, 14 - Chapter 10 Class 12 Vector Algebra - Part 2

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Ex 10.2, 14 Show that the vector š‘– Ģ‚ + š‘— Ģ‚ + š‘˜ Ģ‚ is equally inclined to the axes OX, OY and OZ. Let š‘Ž āƒ— = š‘– Ģ‚ + š‘— Ģ‚ + š‘˜ Ģ‚ = 1š‘– Ģ‚ + 1š‘— Ģ‚ + 1š‘˜ Ģ‚ A vector is equally inclined to OX, OY, OZ i.e. X, Y and Z axes respectively, if its direction cosines are equal. Direction ratios of š‘Ž āƒ— are š‘Ž = 1, b = 1 , c = 1 Magnitude of š‘Ž āƒ— = √(12+12+12) |š‘Ž āƒ— | = √(1+1+1) = √3 Direction cosines OF š‘Ž āƒ— are (š‘Ž/|š‘Ž āƒ— | ,š‘/|š‘Ž āƒ— | ,š‘/|š‘Ž āƒ— | ) = (1/√3,1/√3,1/√3) Since the direction cosines are equal, š‘Ž āƒ— = š‘– Ģ‚ + š‘— Ģ‚ + š‘˜ Ģ‚ is equally inclined to OX, OY and OZ

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