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Misc 4 (MCQ) - Chapter 8 Class 12 Application of Integrals
Last updated at August 2, 2026 by Teachoo
Area bounded by curve and horizontal or vertical line
Chapter 8 Class 12 Application of Integrals
Concept wise
- Area under curve
-
Area bounded by curve and horizontal or vertical line
- Area between curve and line
- Area between curve and curve
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Transcript
Misc 4 Area bounded by the curve š¦=š„3, the š„-axis and the ordinates š„ = ā2 and š„ = 1 is (A) ā 9 (B) (ā15)/4 (C) 15/4 (D) 17/4 Area Required = Area ABO + Area DCO Area ABO Area ABO =ā«_(ā2)^0ā暦 šš„ć Here, š¦=š„^3 Therefore, Area ABO =ā«_(āš)^šāćš^š š šć ć=[š„^4/4]ć_(ā2)^0 =1/4 [0ā(ā2)^4 ] =1/4 Ć (ā16) =ā4 Since Area is always positive, Area ABO = 4 Area DCO Area DCO = ā«_0^1ā暦 šš„ć =ā«_š^šāćš^š š šć =[š„^4/4]_0^1 =1/4 [1^3ā0^3 ] =š/š Now, Area Required = Area ABO + Area DCO =4+1/4 =šš/š square units So, the correct answer is (d) ā“ D is the Correct Option So, the correct answer is (d)
