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Ex 8.1, 13 - Chapter 8 Class 12 Application of Integrals (Term 2)
Last updated at Aug. 11, 2021 by Teachoo
Area bounded by curve and horizontal or vertical line
Ex 8.1, 12 (MCQ)
Ex 8.1, 7
Ex 8.1, 1
Ex 8.1, 11
Example 11
Ex 8.1, 2 Important
Ex 8.1, 8 Important
Example 3
Misc 3
Ex 8.1, 13 (MCQ) Important You are here
Misc 1 (i)
Ex 8.1, 3
Example 5 Important
Misc 5 Important
Example 13 Important Deleted for CBSE Board 2023 Exams
Example 12
Misc 16 (MCQ)
Misc 17 (MCQ) Important
Chapter 8 Class 12 Application of Integrals
Concept wise
- Area under curve
-
Area bounded by curve and horizontal or vertical line
- Area between curve and line
- Area between curve and curve
Transcript
Ex 8.1, 13 Area of the region bounded by the curve π¦2=4π₯, π¦-axis and the line π¦ = 3 is (A) 2 (B) 9/4 (C) 9/3 (D) 9/3 Given curve π¦^2=4π₯ We have to find area between y-axis and line y = 3 β΄ We have to find area of AOB Area of AOB = β«1_0^3βγπ₯ ππ¦γ We know that y2 = 4x x = π¦^2/4 Now, Area of AOB = β«1_0^3βγπ₯ ππ¦γ = β«1_0^3βγπ¦^2/4 ππ¦γ = 1/4 β«1_0^3βγπ¦^2 ππ¦γ = 1/4 [π¦^3/3]_0^3 = 1/4 [(3^3 β 0^3)/3] = 1/4 [27/3] = π/π Hence, option (B) is correct
