Area of triangle
Last updated at August 2, 2026 by Teachoo
Transcript
Ex 4.2, 1 Find area of the triangle with vertices at the point given in each of the following: (1, 0), (6, 0), (4, 3) The area of triangle is given by ā = š/š |ā 8(š±š&š²š&š@š±š&š²š&š@š±š&š²š&š)| Here, x1 = 1 , y1 = 0 x2 = 6 ,y2 = 0 x3 = 4 ,y3 = 3 ā = š/š |ā 8(š&š&š@š&š&š@š&š&š)| = 1/2 (1|ā 8(0&1@3&1)|ā0|ā 8(6&1@4&1)|+1|ā 8(6&0@4&3)|) = 1/2 (1(0 ā 3) ā 0(6 ā 4) + 1 (18 ā 0)) = 1/2 (1(ā3) + 0 + 1 (18) ) = 1/2 [ā3 + 18 ] = šš/š Thus, the required area of triangle is šš/š square units