Area of triangle
Last updated at August 21, 2026 by Teachoo
Transcript
Ex 4.2, 1 Find area of the triangle with vertices at the point given in each of the following: (1, 0), (6, 0), (4, 3) The area of triangle is given by โ = ๐/๐ |โ 8(๐ฑ๐&๐ฒ๐&๐@๐ฑ๐&๐ฒ๐&๐@๐ฑ๐&๐ฒ๐&๐)| Here, x1 = 1 , y1 = 0 x2 = 6 ,y2 = 0 x3 = 4 ,y3 = 3 โ = ๐/๐ |โ 8(๐&๐&๐@๐&๐&๐@๐&๐&๐)| = 1/2 (1|โ 8(0&1@3&1)|โ0|โ 8(6&1@4&1)|+1|โ 8(6&0@4&3)|) = 1/2 (1(0 โ 3) โ 0(6 โ 4) + 1 (18 โ 0)) = 1/2 (1(โ3) + 0 + 1 (18) ) = 1/2 [โ3 + 18 ] = ๐๐/๐ Thus, the required area of triangle is ๐๐/๐ square units