Ex 4.2,1 (i) - Find Area of Triangle with vertices (1, 0), (6, 0), (4, - Ex 4.2

part 2 - Ex 4.2,1 (i) - Ex 4.2 - Serial order wise - Chapter 4 Class 12 Determinants

Remove Ads Take short quiz All Quiz and Worksheets
Teachoo ยท Class 12 Explore Class 12

Transcript

Ex 4.2, 1 Find area of the triangle with vertices at the point given in each of the following: (1, 0), (6, 0), (4, 3) The area of triangle is given by โˆ† = ๐Ÿ/๐Ÿ |โ– 8(๐ฑ๐Ÿ&๐ฒ๐Ÿ&๐Ÿ@๐ฑ๐Ÿ&๐ฒ๐Ÿ&๐Ÿ@๐ฑ๐Ÿ‘&๐ฒ๐Ÿ‘&๐Ÿ)| Here, x1 = 1 , y1 = 0 x2 = 6 ,y2 = 0 x3 = 4 ,y3 = 3 โˆ† = ๐Ÿ/๐Ÿ |โ– 8(๐Ÿ&๐ŸŽ&๐Ÿ@๐Ÿ”&๐ŸŽ&๐Ÿ@๐Ÿ’&๐Ÿ‘&๐Ÿ)| = 1/2 (1|โ– 8(0&1@3&1)|โˆ’0|โ– 8(6&1@4&1)|+1|โ– 8(6&0@4&3)|) = 1/2 (1(0 โ€“ 3) โ€“ 0(6 โ€“ 4) + 1 (18 โ€“ 0)) = 1/2 (1(โ€“3) + 0 + 1 (18) ) = 1/2 [โ€“3 + 18 ] = ๐Ÿ๐Ÿ“/๐Ÿ Thus, the required area of triangle is ๐Ÿ๐Ÿ“/๐Ÿ square units

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.