In a 2D plane,
For three points
Β Β A (x _{ 1 } , y _{ 1 } ),
Β B (x _{ 2 } , y _{ 2 } ),
Β C (x _{ 3 } , y _{ 3 } )
Find area of triangle with vertices (3, 8), (4, 2), (5, 1)
Check solution  Example 17
Important Points
There are some points to note:

If
Area
of triangle
= 0
,
then the three points are collinear

If the value of determinant comes negative, we will take the
positive value as area
Example
Therefore,
Area = 45 square units

If area is given,
We take both positive and negative value of determinant
Example
If Area = 3 square units
Β
Check the questions below to learn more
Β
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