


Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Solving by simplifying det.
Question 6 Deleted for CBSE Board 2024 Exams
Question 9 Important Deleted for CBSE Board 2024 Exams
Question 8 Deleted for CBSE Board 2024 Exams
Question 7 Important Deleted for CBSE Board 2024 Exams
Question 9 Important Deleted for CBSE Board 2024 Exams
Question 4 Important Deleted for CBSE Board 2024 Exams
Question 6 Important Deleted for CBSE Board 2024 Exams
Question 14 Important Deleted for CBSE Board 2024 Exams
Solving by simplifying det.
Last updated at May 29, 2023 by Teachoo
Misc 2(Method 1) Evaluate cos cos cos sin sin sin cos 0 sin cos sin sin cos cos cos cos sin sin sin cos 0 sin cos sin sin cos Expanding Determinant along C1 = cos cos cos 0 sin sin cos cos sin sin 0 sin cos sin sin cos sin sin sin = cos cos (cos cos 0) cos sin ( sin cos 0) sin ( sin2 sin cos2 sin ) = cos cos ( cos cos ) cos sin ( sin cos ) + sin2 sin2 + cos2 sin2 = cos2 cos2 + cos2 sin2 + sin2 ( sin2 + cos2 ) = cos2 (1) + sin2 (1) = cos 2 + sin2 = 1 Misc 2(Method 2) Evaluate cos cos cos sin sin sin cos 0 sin cos sin sin cos Let = cos cos cos sin sin sin cos 0 sin cos sin sin cos = cos sin cos sin sin cos 0 cos sin sin .cos Taking common cos from R1 & sin from R3 = cos .sin cos sin tan sin cos 0 cos sin co Applying R1 R1 R3 = cos .sin cos sin tan sin cos 0 cos sin co Expanding determinant along R1 = cos . sin 0 cos 0 sin cot 0 sin 0 cos cot (tan cot ) sin cos cos sin = cos . sin 0 0 (tan cot ) sin cos cos sin = cos sin ( (tan + cot ) ( sin2 cos2 )) = cos sin ( tan + cot ) (sin2 + cos2 ) = cos sin (tan + cot ) (1) = cos sin sin cos + cos sin = cos sin + cos sin = cos sin cos (1) = 1