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Last updated at Jan. 22, 2020 by Teachoo

Transcript

Ex 4.1, 7 Find values of x, if (i) |■8(2&4@5&1)| = |■8(2x&4@6&x)|Calculating |■8(2&4@5&1)| = 2(1) – 5(4) = 2 – 20 = – 18 Calculating |■8(2x&4@6&x)| = 2x(x) – 6 × 4 = 2x2 – 24 Now |■8(2&4@5&1)| = |■8(2x&4@6&x)| Putting values −18 = 2x2 – 24 2x2 – 24 = −18 2x2 = −18 + 24 2x2 = 6 x2 = 6/2 x2 = 3 x = ± √𝟑 Hence, value of x is ± √3

Finding determinant of a 2x2 matrix

Chapter 4 Class 12 Determinants

Concept wise

- Finding determinant of a 2x2 matrix
- Evalute determinant of a 3x3 matrix
- Area of triangle
- Equation of line using determinant
- Finding Minors and cofactors
- Evaluating determinant using minor and co-factor
- Find adjoint of a matrix
- Finding Inverse of a matrix
- Inverse of two matrices and verifying properties
- Finding inverse when Equation of matrice given
- Checking consistency of equations
- Find solution of equations- Equations given
- Find solution of equations- Statement given
- Verifying properties of a determinant
- Two rows or columns same
- Whole row/column zero
- Whole row/column one
- Making whole row/column one and simplifying
- Proving Determinant 1 = Determinant 2
- Solving by simplifying det.
- Using Property 5 (Determinant as sum of two or more determinants)

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.