Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Last updated at May 29, 2023 by Teachoo
Ex 4.1, 6 If A = [■8(1&1&−[email protected]&1&−[email protected]&4&−9)], find |A| |A| = |■8(1&1&−[email protected]&1&−[email protected]&4&−9)| = 1 |■8(1&−[email protected]&−9)| – 1 |■8(2&−[email protected]&−9)| + (–2) |■8(2&[email protected]&4)| = 1 (1(–9) – 4(–3)) – 1 (2( –9) – 5(–3)) –2(2(4) – 5(1)) = 1 (−9 + 12) + 1 (−18 + 15) – 2 (8 – 5) = 1(3) − 1 (−3) – 2 (3) = 3 + 3 – 6 = 6 – 6 = 0 Hence, |A|= 0