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  1. Chapter 4 Class 12 Determinants
  2. Serial order wise

Transcript

Ex 4.1, 6 If A = [■8(1&1&−2@2&1&−3@5&4&−9)], find |A| |A| = |■8(1&1&−2@2&1&−3@5&4&−9)| = 1 |■8(1&−3@4&−9)| – 1 |■8(2&−3@5&−9)| + (–2) |■8(2&1@5&4)| = 1 (1(–9) – 4(–3)) – 1 (2( –9) – 5(–3)) –2(2(4) – 5(1)) = 1 (−9 + 12) + 1 (−18 + 15) – 2 (8 – 5) = 1(3) − 1 (−3) – 2 (3) = 3 + 3 – 6 = 6 – 6 = 0 Hence, |A|= 0

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.