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Last updated at March 16, 2023 by Teachoo
Ex 4.1, 5 Evaluate the determinant (i) |■8(3&−1&−[email protected]&0&−[email protected]&−5&0)| |■8(3&−1&−[email protected]&0&−[email protected]&−5&0)| = 3 |■8(0&−[email protected]−5&0)| – (–1) |■8(0&−[email protected]&0)| +(–2) |■8(0&[email protected]&−5)| = 3 (0(0) – (–5) (–1) ) + 1 (0(0) – 3(– 1)) – 2 (0(–5) – 3(0)) = 3(0 – 5) + 1 (0 + 3) – 2 (0 – 0) = 3(–5) + 1 (3) + 0 = –15 + 3 = – 12