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Ex 4.1, 7 (ii) - Chapter 4 Class 12 Determinants (Term 1)
Last updated at Aug. 18, 2021 by Teachoo
Chapter 4 Class 12 Determinants
Serial order wise
Transcript
Ex 4.1, 7 Find values of x, if (ii) |■8(2&[email protected]&5)| = |■8(𝑥&[email protected]𝑥&5)| Calculating |■8(2&[email protected]&5)| = 2(5) – 4 (3) = 10 – 2 = –2 Calculating |■8(𝑥&[email protected]𝑥&5)| = x(5) – 2x (3) = 5x – 6x = –x Now, given that |■8(2&[email protected]&5)| = |■8(𝑥&[email protected]𝑥&5)| Putting values –2 = – x 2 = x x = 2 Hence value of x is 2
