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Ex 4.1, 7 - Chapter 4 Class 12 Determinants - Part 3

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Ex 4.1, 7 Find values of x, if (ii) |■8(2&[email protected]&5)| = |■8(𝑥&[email protected]𝑥&5)| Calculating |■8(2&[email protected]&5)| = 2(5) – 4 (3) = 10 – 2 = –2 Calculating |■8(𝑥&[email protected]𝑥&5)| = x(5) – 2x (3) = 5x – 6x = –x Now, given that |■8(2&[email protected]&5)| = |■8(𝑥&[email protected]𝑥&5)| Putting values –2 = – x 2 = x x = 2 Hence value of x is 2

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.