Ex 4.1, 7 (ii) - Chapter 4 Class 12 Determinants

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Ex 4.1, 7 Find values of x, if (ii) |■8(2&3@4&5)| = |■8(𝑥&3@2𝑥&5)| Now, given that |■8(2&3@4&5)| = |■8(𝑥&3@2𝑥&5)| Putting values –2 = – x 2 = x x = 2 Hence value of x is 2 Calculating |■8(2&3@4&5)| = 2(5) – 4 (3) = 10 – 2 = –2 Calculating |■8(𝑥&3@2𝑥&5)| = x(5) – 2x (3) = 5x – 6x = –x

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo