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![Ex 3.2, 7 (i) Class 12 - Matrices - Find X and Y, if X + Y = [] and X- - Ex 3.2](https://cdn.teachoo.com/9dc9e890-2a84-4e99-8320-b8e5cdd3641c/slide23.jpg)
Ex 3.2, 7 (i) - Chapter 3 Class 12 Matrices
Last updated at August 2, 2026 by Teachoo
Chapter 3 Class 12 Matrices
Concept wise
- Formation and order of matrix
- Types of matrices
- Equal matrices
-
Addition/ subtraction of matrices
- Statement questions - Addition/Subtraction of matrices
- Multiplication of matrices
- Statement questions - Multiplication of matrices
- Solving Equation
- Finding unknown - Element
- Finding unknown - Matrice
- Transpose of a matrix
- Symmetric and skew symmetric matrices
- Proof using property of transpose
- Inverse of matrix using elementary transformation
- Proof using mathematical induction
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Transcript
Ex 3.2, 7 Find X and Y, if (i) X + Y = [■8(7&0@2&5)] and X – Y = [■8(3&0@0&3)] Let X + Y = [■8(7&0@2&5)] X – Y = [■8(3&0@0&3)] Adding (1) and (2) X + Y + X – Y = [■8(7&0@2&5)] + [■8(3&0@0&3)] X + Y + X – Y = [■8(7+3&0+0@2+0&5+3)] 2X + 0 = [■8(10&0@2&8)] 2X = [■8(𝟏𝟎&𝟎@𝟐&𝟖)] X = 1/2 [■8(10&0@2&8)] X = [■8(10/2&0/2@2/2&8/2)] X = [■8(𝟓&𝟎@𝟏&𝟒)] Thus, X = [■8(5&0@1&4)] Putting value of X in (1) X + Y = [■8(7&0@2&5)] Y = [■8(7&0@2&5)] – X Y = [■8(𝟕&𝟎@𝟐&𝟓)] – [■8(𝟓&𝟎@𝟏&𝟒)] Y = [■8(7−5&0−0@2−1&5−4)] Y = [■8(𝟐&𝟎@𝟏&𝟏)] Hence, X = [■8(𝟓&𝟎@𝟏&𝟒)] & Y = [■8(𝟐&𝟎@𝟏&𝟏)]
