Check sibling questions

Example 28 - Find a matrix D such that CD - AB = O - Examples

Example 28 - Chapter 3 Class 12 Matrices - Part 2
Example 28 - Chapter 3 Class 12 Matrices - Part 3 Example 28 - Chapter 3 Class 12 Matrices - Part 4 Example 28 - Chapter 3 Class 12 Matrices - Part 5 Example 28 - Chapter 3 Class 12 Matrices - Part 6 Example 28 - Chapter 3 Class 12 Matrices - Part 7

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Example 25 Let A = [■8(2&−[email protected]&4)], B=[■8(5&[email protected]&4)], C = [■8(2&[email protected]&8)] find a matrix D such that CD – AB = O Order of A = 2 × 2 & Order of B = 2 × 2 Order of AB = 2 × 2 Since we are doing CD – AB Order of CD = Order of AB Order of CD = 2 × 2 Order of C = 2 × 2 So, order of D = × Let D = [■8(a&[email protected]&d)] Now, given CD – AB = O [■8(2&[email protected]&8)] [■8(a&[email protected]&d)] − [■8(2&−[email protected]&4)][■8(5&[email protected]&4)] = O [■8(2(a)+5(c)&2(b)+5(d)@3(a)+8(c)&3(b)+8(d))] – [■8(2(5)+(−1)7&2(2)+(−1)(4)@3(5)+4(7)&3(2)+4(4))] = O [■8(2a+5c&[email protected]+8c&3b+8d)] – [■8(10−7&4−[email protected]+28&6+16)] = O [■8(2a+5c&[email protected]+8c&3b+8d)] – [■8(3&[email protected]&22)] = O [■8(2a+5c−3&2b+5d−[email protected]+8c−43&3b+8d−22)]=[■8(0&[email protected]&0)] Since matrices are equal, Corresponding elements are equal Hence, 2a + 5c – 3 = 0 3a + 8c – 43 = 0 2b + 5d = 0 3b + 8d – 22 = 0 Solving (1) 2a + 5c – 3 = 0 2a + 5c = 3 2a = 3 – 5c a = (3 − 5𝑐)/2 Putting value of a in (2) 3a + 8c – 43 = 0 3((3−5𝑐)/2) + 8c – 43 = 0 (3(3 − 5𝑐) + 2(8𝑐) − 2(43))/2 = 0 9 – 15c + 16c – 86 = 0 − 15c + 16c – 86 + 9 = 0 c – 77 = 0 c = 77 From (1) 2a + 5c – 3 = 0 Putting value of c = 77 2a + 5 × 77 – 3 = 0 2a + 385 – 3 = 0 2a + 382 = 0 2a = –382 a = (−382)/2 a = −191 From (3) 2b + 5d = 0 2b = − 5d b = ((− 5)/2)d From (4) 3b + 8d – 22 = 0 Putting value of b = ((− 5)/2)d 3((− 5)/2)d + 8d − 22 = 0 (−15𝑑)/2 + 8d – 22 = 0 (−15𝑑 + 16𝑑 − 44)/2 = 0 d – 44 = 0 × 2 d – 44 = 0 d = 44 From (3) 2b + 5d = 0 Putting value of d = 44 2b + 5 × 44 = 0 2b + 220 = 0 2b = –220 b = (−220)/2 b = −110 Hence, a = −191, b = −110 , c = 77 , d = 44 Thus, Matrix D is = [■8(𝑎&𝑏@𝑐&𝑑)] = [■8(−𝟏𝟗𝟏&−𝟏𝟏𝟎@𝟕𝟕&𝟒𝟒)]

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.