Ex 3.2, 5 - Chapter 3 Class 12 Matrices

Last updated at August 20, 2026 by

Ex 3.2, 5 - Compute 3A - 5B if A = [2/3 1 5/3 1/3 2/3 4/3 7/3 - Ex 3.2

part 2 - Ex 3.2, 5 - Ex 3.2 - Serial order wise - Chapter 3 Class 12 Matrices

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Ex 3.2, 5 If A = [■8(2/3&1&5/3@1/3&2/3&4/3@7/3&2&2/3)] and B = [■8(2/5&3/5&1@1/5&2/5&4/5@7/5&6/5&2/5)] ,then compute 3A – 5B 3A – 5B = 3 [■8(2/3&1&5/3@1/3&2/3&4/3@7/3&2&2/3)] - 5 [■8(2/5&3/5&1@1/5&2/5&4/5@7/5&6/5&2/5)] = [■8(2/3 ×3&1×3&5/3×3@1/3×3&2/3×3&4/3×3@7/3×3&2×3&2/3×3)] – [■8(2/5×5&3/5×5&1×5@1/5×5&2/5×5&4/5×5@7/5×5&6/5×5&2/5×5 )] = [■8(𝟐&𝟑&𝟓@𝟏&𝟐&𝟒@𝟕&𝟔&𝟐)] – [■8(𝟐&𝟑&𝟓@𝟏&𝟐&𝟒@𝟕&𝟔&𝟐)] = [■8(2−2&3−3&5−5@1−1&2−2&4−4@7−7&6−6&2−2)] = [■8(𝟎&𝟎&𝟎@𝟎&𝟎&𝟎@𝟎&𝟎&𝟎)] Hence, 3A – 5B = [■8(0&0&0@0&0&0@0&0&0)]

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