Ex 3.2, 2
Compute the following:
(i) [■8(a&b@−b&a)] + [■8(a&b@b&a)]
[■8( a&b@−b&a)] + [■8(a&b@b&a)]
= [■8(a+a&b+b@b+b&a+a)]
= [■8(2a&2b@0&2a)]
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