Question 5 — A motorbike moving with initial - Questions at the end of the chapter - Chapter 4 - Describing Motion Around Us (Exploration)

Last updated at July 16, 2026 by

A motorbike moving with initial velocity 28 m s⁻¹ and constant acceleration stops after travelling 98 m. Find the acceleration of the motorbike and the time taken to come to a stop.

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u = 28 m s -1 , v = 0, s = 98 m .

Using v 2 = u 2 + 2as : 0 = 28 2 + 2a(98) ⇒ a = -784 196 = -4 m s -2 .

Using v = u + at : 0 = 28 + (-4)t ⇒ t = 7 s .

Quantity Value
Acceleration a −4 m/s²
Time to stop t 7 s
← Back to: 4.3 Kinematic Equations for Motion in a Straight Line with Constant Acceleration
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