Rohan studies science from 6 PM to 7:30 PM at home. Consider the tip of the minute’s hand of the wall clock. During the given time interval, what is its: (i) distance travelled, (ii) displacement, (iii) speed, and (iv) velocity. The length of the minute’s hand is 7 cm (Fig. 4.32).

Show Answer Hide Answer

6:00 to 7:30 = 90 min = 1.5 h. The minute hand makes 90 60 = 1.5 revolutions. Radius R = 7 cm .

(i) Distance = 1.5 × 2π R = 1.5 × 2 × 22 7 × 7 = 1.5 × 44 = 66 cm .

(ii) After 1.5 turns the tip is diametrically opposite its start, so displacement = 2R = 14 cm .

(iii) Speed = 66 cm 90 min ≈ 0.73 cm min -1 (i.e. 44 cm h⁻¹).

(iv) Velocity = 14 cm 90 min ≈ 0.16 cm min -1 , directed from the start position to the end position.

Quantity Value
Distance 66 cm
Displacement 14 cm
Speed ≈ 0.73 cm/min
Velocity ≈ 0.16 cm/min
← Back to: 4.4.1 Uniform circular motion
Remove Ads
CA Maninder Singh's photo - Co-founder, Teachoo

Made by

CA Maninder Singh

CA Maninder Singh is a Chartered Accountant with 16+ years of practical experience and 20+ years of teaching experience. At Teachoo, he simplifies Accounts, Tax and GST with step-by-step examples so students can apply concepts confidently in exams and real life.

For an uninterrupted learning experience, students can use Teachoo Black to remove ads and focus better.