A car starts from rest and its velocity reaches 24 m s⁻¹ in 6 s. Find the average acceleration and the distance travelled in these 6 s.

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u = 0, v = 24 m s -1 , t = 6 s .

Acceleration a = v - u t = 24 - 0 6 = 4 m s -2 .

Distance s = ut + 1 2 at 2 = 0 + 1 2 (4)(6 2 ) = 72 m .

Quantity Value
Average acceleration a 4 m/s²
Distance travelled s 72 m
← Back to: 4.3 Kinematic Equations for Motion in a Straight Line with Constant Acceleration
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