A car starts from rest and its velocity reaches 24 m s⁻¹ in 6 s. Find the average acceleration and the distance travelled in these 6 s.
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u = 0, v = 24 m s -1 , t = 6 s .
Acceleration a = v - u t = 24 - 0 6 = 4 m s -2 .
Distance s = ut + 1 2 at 2 = 0 + 1 2 (4)(6 2 ) = 72 m .
| Quantity | Value |
|---|---|
| Average acceleration a | 4 m/s² |
| Distance travelled s | 72 m |